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IBM C6030-041 Exam Syllabus Topics:

IBM Programming with IBM Enterprise PL/I Sample Questions:

Question 1

CORRECT TEXT
Given the following code, what procedure will be accepted by the compiler?
DCL A DIM (10) CHAR (100) VAR BASED (P);
DCL P PTR;
ALLOCATE A;
CALL SUB(P);

A. SUB: PROCEDURE (P);
DCL P PTR;
DCL A DIM (10) CHAR (100) VAR BASED (P); END SUB;
B. SUB: PROCEDURE (P);
DCL P PTR;
DCL A DIM (10) CHAR (*) VAR BASED (P);
END SUB;
C. SUB: PROCEDURE (P);
DCL P PTR;
DCL A DIM (*) CHAR (*) VAR BASED (P);
END SUB;
D. SUB: PROCEDURE (P);
DCL P PTR;
DCL A DIM (*) CHAR (100) VAR BASED (P);
END SUB;

Question 2

CORRECT TEXT
What is the result, if any, of executing the following code?
DCL B DEC FIXED(15,3) INIT(12345.12);
DCL C PlC '9999999999' INIT (0);
C = B;

A. There is no result, because DEC FIXED cannot be assigned to PlC.
B. The result in C is
12345 with 5 leading zeroes.
C. The result in C is 1234512 with 3 leading zeroes.
D. There is no result, because B contains a decimal point.

Question 3

CORRECT TEXT
What is the result, if any, of executing the following code?
DCL A CHAR(2) INIT(' ');
DCL B BIT(2) INIT('11'B);
A = ^B;

A. The value of A is unpredictable.
B. There is no result, because the syntax is wrong.
C. The value of A is '00'.
D. The value of A is'11'.

Question 4

CORRECT TEXT
What is the value of A after executing the following code?
DCL A CHAR(7) INIT ('ABCDEFG'); DCLB CHAR(10) INIT ('0123456789');
SUBSTR(A,4) = SUBSTR(B,5,3);

A. 'ABC456 '
B. 'ABCD456'
C. 'ABC4560'
D. 'ABC4567'

Question 5

Given the following program, which subroutine improperly uses pointers to address memory and could lead to data corruption or an exception?

A. SUB3
B. SUB1
C. SUB2
D. PROC OPTIONS(MAIN);
DCL
1 X,
2 X1 CHAR(76),
2 X2 PIC'9999';
DCL Y CHAR(20);
CALL SUB1( ADDR(X));
CALL SUB2( ADDR(X));
CALL SUB3( ADDR(X));
CALL SUB4( ADDR(X));
SUB 1: PROC( P);
DCL P POINTER;
DCL
1 XBASED(P),
2 X1 CHAR(76),
2 X2 PIC'9999'
X = ";
END;
SUB2: PROC( P);
DCL P POINTER;
DCL
1 X BASED(P),
2 X 1 PIC'(76)X'
2 X 2 PIC'9999'
X = ";
END;
SUB3: PROC( P);
DCL P POINTER;
DCL X CHAR(60) BASED(P);
X = ";
END;
SUB4: PROC( P );
DCL P POINTER;
DCLX CHAR(100) BASED(P);
X = ";
END; END;
E. SUB4

Solutions: